integral of (2sin(x)-5e^x)

Lösung

\int (2 sin (x) - 5 e^{x}) d x

- 2 cos (x) - 5 e^{x} + C

Schritte zur Lösung

\int 2 sin (x) - 5 e^{x} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 sin (x) d x - \int 5 e^{x} d x

\int 2 sin (x) d x = - 2 cos (x)

\int 5 e^{x} d x = 5 e^{x}

= - 2 cos (x) - 5 e^{x}

Füge eine Konstante zur Lösung hinzu

= - 2 cos (x) - 5 e^{x} + C

\int \frac{1}{2} sin (2 θ) d θ

\frac{\partial}{\partial x} (x^{2} + 2 y^{2} - x^{2} y - 1)

x \to - π lim ((x + π) csc (x))

8 t \frac{d y}{d t} + y = t^{7}

\frac{d}{d x} (\frac{x ^{2}}{x ^{4} + x ^{2} + 1})