derivative of x^3-6x^2+8x

解答

\frac{d}{d x} (x^{3} - 6 x^{2} + 8 x)

3 x^{2} - 12 x + 8

求解步骤

\frac{d}{d x} (x^{3} - 6 x^{2} + 8 x)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (8 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (8 x) = 8

= 3 x^{2} - 12 x + 8

\int (7 x^{2}) e x^{3} + 1 d x

f (x) = - 4 sin (4 x)

t an g e n t y = x + \frac{6}{x}, (3, 5)

81 y^{^{''}} + 180 y^{^{'}} + 125 y = 0, y (3) = 6, y^{^{'}} (3) = 6

\frac{d}{d x} (8 cos^{2} (x))