derivative sqrt(15t^2+9)

Lösung

ableitung von

15 t^{2} + 9

\frac{15 t}{15 t ^{2} + 9}

Schritte zur Lösung

\frac{d}{d t} (15 t^{2} + 9)

Wende die Kettenregel an:

\frac{1}{2 15 t ^{2} + 9} \frac{d}{d t} (15 t^{2} + 9)

= \frac{1}{2 15 t ^{2} + 9} \frac{d}{d t} (15 t^{2} + 9)

\frac{d}{d t} (15 t^{2} + 9) = 30 t

= \frac{1}{2 15 t ^{2} + 9} \cdot 30 t

Vereinfache

\frac{1}{2 15 t ^{2} + 9} \cdot 30 t : \frac{15 t}{15 t ^{2} + 9}

= \frac{15 t}{15 t ^{2} + 9}

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