derivative of ln((x+y/(x-y)))

Lösung

\frac{d}{d x} (ln (\frac{x + y}{x - y}))

\frac{2 x \frac{d y}{d x} - 2 y}{( x + y ) ( x - y )}

Schritte zur Lösung

\frac{d}{d x} (ln (\frac{x + y}{x - y}))

Wende die Kettenregel an:

\frac{1}{\frac{x + y}{x - y}} \frac{d}{d x} (\frac{x + y}{x - y})

= \frac{1}{\frac{x + y}{x - y}} \frac{d}{d x} (\frac{x + y}{x - y})

\frac{d}{d x} (\frac{x + y}{x - y}) = \frac{2 x \frac{d y}{d x} - 2 y}{( x - y ) ^{2}}

= \frac{1}{\frac{x + y}{x - y}} \cdot \frac{2 x \frac{d y}{d x} - 2 y}{( x - y ) ^{2}}

Vereinfache

\frac{1}{\frac{x + y}{x - y}} \cdot \frac{2 x \frac{d y}{d x} - 2 y}{( x - y ) ^{2}} : \frac{2 x \frac{d y}{d x} - 2 y}{( x + y ) ( x - y )}

= \frac{2 x \frac{d y}{d x} - 2 y}{( x + y ) ( x - y )}

\frac{d}{d x} (ln (2 x^{4} e^{3 x} (x^{2} + x + 1)^{5}))

\int \frac{3 - x}{3 - x ^{2}} d x

\int_{- 2}^{5} - 2 d x

\int \frac{x - 2}{( x ^{2} + x + 2 ) ( x ^{2} + 2 )} d x

\frac{d}{d x} (x ln (x) - x + 1)