What is the integral from 0 to pi of 3sin(x) ?

The integral from 0 to pi of 3sin(x) is 6

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integral from 0 to pi of 3sin(x)

\int_{0}^{π} 3 sin (x) d x

6

Solution steps

\int_{0}^{π} 3 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 3 [- cos (x)]_{0}^{π}

Compute the boundaries:

2

= 3 \cdot 2

Simplify

= 6

\int \frac{2 x ^{2} + x - 4}{x ^{3} - x ^{2} - 2 x} d x

\frac{\partial}{\partial x} (7 sin (x) sin (y))

\frac{d}{d x} (\frac{6}{5})

\frac{d}{d t} (6 arctan (t))

\frac{d}{d x} (24 e^{- 3 x})

What is the integral from 0 to pi of 3sin(x) ?
The integral from 0 to pi of 3sin(x) is 6