integral from 0 to 1-|x-1| of 1

Lösung

\int_{0}^{1 - ∣ x - 1 ∣} 1 d y

- ∣ x - 1 ∣ + 1

Schritte zur Lösung

\int_{0}^{1 - ∣ x - 1 ∣} 1 d y

Integral einer Konstanten :

\int a d x = a x

= [1 \cdot y]_{0}^{1 - ∣ x - 1 ∣}

Vereinfache

= [y]_{0}^{1 - ∣ x - 1 ∣}

Berechne die Grenzen:

- ∣ x - 1 ∣ + 1

= - ∣ x - 1 ∣ + 1

\frac{d}{d x} (3 (x^{2} - 1)^{2})

\frac{\partial}{\partial x} (- cos^{2} (x))

\int \frac{x}{x ^{2} + 36} d x

\frac{\partial}{\partial x} ((3 + x^{2} - 3 y^{2})^{\frac{1}{2}})

t a y l or x^{2} e^{3 x}