What is the derivative of y=e^{x+1}+1 ?

The derivative of y=e^{x+1}+1 is e^{x+1}

What is the first derivative of y=e^{x+1}+1 ?

The first derivative of y=e^{x+1}+1 is e^{x+1}

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derivative of

y = e^{x + 1} + 1

e^{x + 1}

Solution steps

\frac{d}{d x} (e^{x + 1} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x + 1}) + \frac{d}{d x} (1)

\frac{d}{d x} (e^{x + 1}) = e^{x + 1}

\frac{d}{d x} (1) = 0

= e^{x + 1} + 0

Simplify

= e^{x + 1}

x \frac{d y}{d x} + 2 y = \frac{1}{x ^{3}}

x^{2} + 7 x - 5

\int (\frac{3}{x} - \frac{x x}{4}) d x

z^{^{'}}

\frac{d}{d x} (y^{2} + x^{2})

What is the derivative of y=e^{x+1}+1 ?
The derivative of y=e^{x+1}+1 is e^{x+1}
What is the first derivative of y=e^{x+1}+1 ?
The first derivative of y=e^{x+1}+1 is e^{x+1}