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tangent 7/x

解答

切线

\frac{7}{x}

解答

y = - \frac{7}{a _{0}^{2}} x + \frac{14}{a _{0}}

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, \frac{7}{a _{0}})

计算

y = \frac{7}{x}

的斜率:

\frac{d y}{d x} = - \frac{7}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{7}{a _{0}^{2}}

找到斜率 m=

- \frac{7}{a _{0}^{2}}

且穿过

(a_{0}, \frac{7}{a _{0}})

的直线:

y = - \frac{7}{a _{0}^{2}} x + \frac{14}{a _{0}}

y = - \frac{7}{a _{0}^{2}} x + \frac{14}{a _{0}}

作图

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