(\partial)/(\partial x)(2e^{-2x}+1/3 e^x)

Lösung

\frac{\partial}{\partial x} (2 e^{- 2 x} + \frac{1}{3} e^{x})

- 4 e^{- 2 x} + \frac{1}{3} e^{x}

Schritte zur Lösung

\frac{\partial}{\partial x} (2 e^{- 2 x} + \frac{1}{3} e^{x})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 e^{- 2 x}) + \frac{\partial}{\partial x} (\frac{1}{3} e^{x})

\frac{\partial}{\partial x} (2 e^{- 2 x}) = - 4 e^{- 2 x}

\frac{\partial}{\partial x} (\frac{1}{3} e^{x}) = \frac{1}{3} e^{x}

= - 4 e^{- 2 x} + \frac{1}{3} e^{x}

\int_{0}^{\frac{π}{6}} tan (2 x) d x

d er i v a t i v e f (x) = 2 e^{x} cos (x)

d er i v a t i v e e^{8 e^{x}}

\int_{5}^{\infty} x e^{- 3 x} d x

\int_{0}^{8} x + 1 d x