integral from 0 to 16 of sqrt(x)-1/4 x

Lösung

\int_{0}^{16} x - \frac{1}{4} x d x

\frac{32}{3}

Dezimale

10.66666 \dots

Schritte zur Lösung

\int_{0}^{16} x - \frac{1}{4} x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{16} x d x - \int_{0}^{16} \frac{1}{4} x d x

\int_{0}^{16} x d x = \frac{128}{3}

\int_{0}^{16} \frac{1}{4} x d x = 32

= \frac{128}{3} - 32

Vereinfache

\frac{128}{3} - 32 : \frac{32}{3}

= \frac{32}{3}

\frac{d}{d x} (\frac{4 x + 5}{8})

s l o p e y = \frac{3}{x}, (5, \frac{3}{5})

in v erse l a pl a ce \frac{s - 1}{s ( s + 1 ) ( s + 2 )}

\int \frac{1}{3 - 5 x ^{2}} d x

\frac{\partial}{\partial x} (x^{3} - 12 x y + 8 y^{3})