What is the solution for (dy)/(dt)=0.03y+3600 ?

The solution for (dy)/(dt)=0.03y+3600 is y=(e^{0.03t+c_{1}})/(0.03)-(3600)/(0.03)

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(dy)/(dt)=0.03y+3600

\frac{d y}{d t} = 0.03 y + 3600

y = \frac{e ^{0.03 t + c_{1}}}{0.03} - \frac{3600}{0.03}

Solution steps

\frac{d y}{d t} = 0.03 y + 3600

Solve separable ODE:

y = \frac{e ^{0.03 t + c_{1}}}{0.03} - \frac{3600}{0.03}

y = \frac{e ^{0.03 t + c_{1}}}{0.03} - \frac{3600}{0.03}

\frac{\partial}{\partial x} (x^{\frac{3}{2}})

\int e^{b x} d x

3 cos (t)

y^{^{''}} - 2 y^{^{'}} + y = 0, y (0) = - 1, y^{^{'}} (0) = - 2

c y^{- 3}

What is the solution for (dy)/(dt)=0.03y+3600 ?
The solution for (dy)/(dt)=0.03y+3600 is y=(e^{0.03t+c_{1}})/(0.03)-(3600)/(0.03)