sum from n=0 to infinity of (2/4)^n

Lösung

n = 0 \sum \infty (\frac{2}{4})^{n}

2

Schritte zur Lösung

n = 0 \sum \infty (\frac{2}{4})^{n}

Geometrischen Test der Reihe anwenden:

2

= 2

\int 5 x + 12 d x

n = 0 \sum \infty n \cdot (\frac{1}{6})^{n}

x y^{^{'}} + 2 y - 2 x^{2} y^{2} = 0

\int \frac{1}{x ^{2} + 6 x + 13} d x

\int_{1}^{4} 3 e^{x} d x