derivative of (2cos(2x+sin(3x)+3)^2)

Lösung

\frac{d}{d x} ((2 cos (2 x) + sin (3 x) + 3)^{2})

2 (2 cos (2 x) + sin (3 x) + 3) (3 cos (3 x) - 4 sin (2 x))

Schritte zur Lösung

\frac{d}{d x} ((2 cos (2 x) + sin (3 x) + 3)^{2})

Wende die Kettenregel an:

2 (2 cos (2 x) + sin (3 x) + 3) \frac{d}{d x} (2 cos (2 x) + sin (3 x) + 3)

= 2 (2 cos (2 x) + sin (3 x) + 3) \frac{d}{d x} (2 cos (2 x) + sin (3 x) + 3)

\frac{d}{d x} (2 cos (2 x) + sin (3 x) + 3) = 3 cos (3 x) - 4 sin (2 x)

= 2 (2 cos (2 x) + sin (3 x) + 3) (3 cos (3 x) - 4 sin (2 x))

d er i v a t i v e y = \frac{A x ^{2}}{x ^{2} - 1}

\frac{d}{d x} (4 x^{3} + 5 x^{2} + x + 6)

\frac{d y}{d x} = 2 y^{2} + x y^{2}

\int \frac{1}{x ^{2} 2 + 9 x ^{2}} d x

\frac{\partial}{\partial y} ((x^{2} + y^{2}) ln (x^{2} + y^{2}))