derivative of (8x+9(9x-10))

Lösung

\frac{d}{d x} ((8 x + 9) (9 x - 10))

144 x + 1

Schritte zur Lösung

\frac{d}{d x} ((8 x + 9) (9 x - 10))

Wende die Produktregel an:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 8 x + 9, g = 9 x - 10

= \frac{d}{d x} (8 x + 9) (9 x - 10) + \frac{d}{d x} (9 x - 10) (8 x + 9)

\frac{d}{d x} (8 x + 9) = 8

\frac{d}{d x} (9 x - 10) = 9

= 8 (9 x - 10) + 9 (8 x + 9)

Vereinfache

8 (9 x - 10) + 9 (8 x + 9) : 144 x + 1

= 144 x + 1

\int x^{2} - 4 x + 4 d x

\frac{d y}{d x} = \frac{cos ( 12 x )}{e ^{12 y}}

\int_{1}^{2} \frac{15}{x ^{3} + 5 x} d x

s im pl i f y xL (x) - x

y^{^{''}} - y^{^{'}} - 6 y = 0, y (0) = 0, y^{^{'}} (0) = 4