integral from-1 to 2 of (x+2-x^2)

Lösung

\int_{- 1}^{2} (x + 2 - x^{2}) d x

\frac{9}{2}

Dezimale

4.5

Schritte zur Lösung

\int_{- 1}^{2} x + 2 - x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x d x + \int_{- 1}^{2} 2 d x - \int_{- 1}^{2} x^{2} d x

\int_{- 1}^{2} x d x = \frac{3}{2}

\int_{- 1}^{2} 2 d x = 6

\int_{- 1}^{2} x^{2} d x = 3

= \frac{3}{2} + 6 - 3

Vereinfache

\frac{3}{2} + 6 - 3 : \frac{9}{2}

= \frac{9}{2}

\frac{d}{d x} (\frac{9}{e ^{x} + e ^{- x}})

\int \frac{x ^{2}}{1 - 2 x ^{2}} d x

\frac{\partial}{\partial x} (ln (3 x^{2} + 4 y^{2} + 2))

n = 1 \sum \infty x^{n}

\int x^{6} e^{- x} d x