y^'+1/x y=-1/x y^2,y(1)=2

Lösung

y^{^{'}} + \frac{1}{x} y = - \frac{1}{x} y^{2}, y (1) = 2

y = \frac{2}{3 x - 2}

Schritte zur Lösung

y^{'} (x) + \frac{1}{x} y = - \frac{1}{x} y^{2}

Solve separable ODE:

y = \frac{2}{3 x - 2}

y = \frac{2}{3 x - 2}

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