derivative of 5x^4-2x^3-3x+2

解答

\frac{d}{d x} (5 x^{4} - 2 x^{3} - 3 x + 2)

20 x^{3} - 6 x^{2} - 3

求解步骤

\frac{d}{d x} (5 x^{4} - 2 x^{3} - 3 x + 2)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{4}) - \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (2)

\frac{d}{d x} (5 x^{4}) = 20 x^{3}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 20 x^{3} - 6 x^{2} - 3 + 0

化简

= 20 x^{3} - 6 x^{2} - 3

y^{^{''}} + 8 y^{^{'}} + 7 y = 0

\int sin (x) cos (x) 1 - sin^{4} (x) d x

\frac{\partial}{\partial x} ((3 y) \cdot (2 x)^{- 1})

p a r i t y f (x) = sin (tan (2 x))

d er i v a t i v e 2 (2 x^{5} - 3 x + 2)^{8}