What is the integral of e^{-4x+pi} ?

The integral of e^{-4x+pi} is -1/4 e^{pi-4x}+C

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integral of e^{-4x+pi}

\int e^{- 4 x + π} d x

- \frac{1}{4} e^{π - 4 x} + C

Solution steps

\int e^{- 4 x + π} d x

e^{- 4 x + π} = e^{π} e^{- 4 x}

= \int e^{π} e^{- 4 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e^{π} \cdot \int e^{- 4 x} d x

Apply u-substitution

: \int - \frac{1}{4} e^{u} d u

= e^{π} \cdot \int - \frac{1}{4} e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= e^{π} (- \frac{1}{4} \cdot \int e^{u} d u)

Use the common integral:

\int e^{u} d u = e^{u}

= e^{π} (- \frac{1}{4} e^{u})

Substitute back

u = - 4 x

= e^{π} (- \frac{1}{4} e^{- 4 x})

Simplify

e^{π} (- \frac{1}{4} e^{- 4 x}) : - \frac{1}{4} e^{π - 4 x}

= - \frac{1}{4} e^{π - 4 x}

Add a constant to the solution

= - \frac{1}{4} e^{π - 4 x} + C

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f (x) = x^{2} + 16

What is the integral of e^{-4x+pi} ?
The integral of e^{-4x+pi} is -1/4 e^{pi-4x}+C