derivative f(x)=(1+3x^2)(x-x^2)

Lösung

ableitung von

f (x) = (1 + 3 x^{2}) (x - x^{2})

- 12 x^{3} + 9 x^{2} - 2 x + 1

Schritte zur Lösung

\frac{d}{d x} ((1 + 3 x^{2}) (x - x^{2}))

Wende die Produktregel an:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 1 + 3 x^{2}, g = x - x^{2}

= \frac{d}{d x} (1 + 3 x^{2}) (x - x^{2}) + \frac{d}{d x} (x - x^{2}) (1 + 3 x^{2})

\frac{d}{d x} (1 + 3 x^{2}) = 6 x

\frac{d}{d x} (x - x^{2}) = 1 - 2 x

= 6 x (x - x^{2}) + (1 - 2 x) (1 + 3 x^{2})

Vereinfache

6 x (x - x^{2}) + (1 - 2 x) (1 + 3 x^{2}) : - 12 x^{3} + 9 x^{2} - 2 x + 1

= - 12 x^{3} + 9 x^{2} - 2 x + 1

\int [(3 - x^{2})^{3}] d x

\int \frac{- 3}{( x - 2 ) ( x ^{2} + 4 )} d x

x \to 2 + lim (2)

\frac{d}{d x} ((3 x + 5)^{7})

\int_{- 1}^{0} (2 x - e^{x}) d x