d/(dt)(k^2sin^2(t))

Lösung

\frac{d}{d t} (k^{2} sin^{2} (t))

k^{2} sin (2 t)

Schritte zur Lösung

\frac{d}{d t} (k^{2} sin^{2} (t))

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= k^{2} \frac{d}{d t} (sin^{2} (t))

Wende die Kettenregel an:

2 sin (t) \frac{d}{d t} (sin (t))

= 2 sin (t) \frac{d}{d t} (sin (t))

\frac{d}{d t} (sin (t)) = cos (t)

= k^{2} \cdot 2 sin (t) cos (t)

Verwende die Doppelwinkelidentität:

2 sin (x) cos (x) = sin (2 x)

= k^{2} sin (2 t)

d er i v a t i v e 2 csc^{3} (x) + 3 c t a (x^{2})

x \to 0 - lim (6 + \frac{1}{x})

\frac{\partial}{\partial x} (y e^{- x y})

\frac{\partial}{\partial x} (\frac{x}{x + 1})

x \to \infty lim (x (1)^{x})