(dy)/(dx)= 1/2 x+1

Lösung

\frac{d y}{d x} = \frac{1}{2} x + 1

y = \frac{x ^{2}}{4} + x + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = \frac{1}{2} x + 1

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = \frac{1}{2} x + 1

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int \frac{1}{2} x + 1 d x

\int \frac{1}{2} x + 1 d x = \frac{x ^{2}}{4} + x + c_{1}

y = \frac{x ^{2}}{4} + x + c_{1}

a re a f (x) = \frac{1}{x}, g (x) = \frac{1}{3}, [2, 5]

d er i v a t i v e \frac{7 u ^{2}}{( u ^{2} + u ) ^{3}}

\int \frac{3 x ^{2}}{1 - x ^{6}} d x

a re a x, x^{2} - 2

x \to 0 lim (3 cos (x))