面积 y=x^3-x^2,y=0

解答

面积

y = x^{3} - x^{2}, y = 0

\frac{1}{12}

十进制

0.08333 \dots

求解步骤

使用面积公式:

\int_{0}^{1} x^{3} - x^{2} d x

解

\int_{0}^{1} x^{3} - x^{2} d x : \frac{1}{12}

面积为:

= \frac{1}{12}

\frac{\partial}{\partial x} (3 x^{2} y^{4} + 1)

\int \frac{1}{x 9 x ^{2} - 4} d x

k = 1 \sum \infty k^{3} \cdot e^{- k^{2}}

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\frac{\partial}{\partial y} (y ln (x^{2} y))