(2y^2+6x)dx+2xydy=0

解答

(2 y^{2} + 6 x) d x + 2 x y d y = 0

y = \frac{- 2 x ^{3} + c _{1}}{x}, y = - \frac{- 2 x ^{3} + c _{1}}{x}

求解步骤

(2 y^{2} + 6 x) d x + 2 x y d y = 0

求解贝努力方程:

y = \frac{- 2 x ^{3} + c _{1}}{x}, y = - \frac{- 2 x ^{3} + c _{1}}{x}

y = \frac{- 2 x ^{3} + c _{1}}{x}, y = - \frac{- 2 x ^{3} + c _{1}}{x}

\frac{d}{d x} (ln (\frac{x + 6}{x - 6}))

\int \frac{tan ^{2} ( 7 x )}{csc ( 7 x )} d x

d er i v a t i v e f (x) = x (x - 6)^{2}

d er i v a t i v e 5 e^{x} + \frac{4}{3 x}

\frac{d}{d x} (2 sin (x) + 1)