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受欢迎的微积分 >

tangent e^{-2t},\at t=0

解答

切线

e^{- 2 t}, at t = 0

解答

y = - 2 t + 1

求解步骤

找到切点:

(0, 1)

计算

y = e^{- 2 t}

的斜率:

\frac{d y}{d t} = - 2 e^{- 2 t}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2

找到斜率 m=

- 2

且穿过

(0, 1)

的直线:

y = - 2 t + 1

y = - 2 t + 1

作图

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