y^'=((x^2-y^2))/(xy),y(2)=5

Lösung

y^{^{'}} = \frac{( x ^{2} - y ^{2} )}{x y}, y (2) = 5

y = \frac{x ^{4} + 184}{2 x}

Schritte zur Lösung

y^{'} (x) = \frac{( x ^{2} - y ^{2} )}{x y}

Solve Bernoulli ODE:

y = \frac{x ^{4} + 184}{2 x}

y = \frac{x ^{4} + 184}{2 x}

t an g e n t f (x) = 4 sec (x), at (\frac{π}{6})

\int \frac{x ^{3}}{x ^{2} + 10 x + 25} d x

\frac{\partial}{\partial x} (lo g_{10} (x + y))

\int t sin (9 t) d t

s l o p e (2.3) (4.4)