What is the solution for y^'=((x^2-y^2))/(xy),y(2)=5 ?

The solution for y^'=((x^2-y^2))/(xy),y(2)=5 is y=(sqrt(x^4+184))/(sqrt(2)x)

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y^'=((x^2-y^2))/(xy),y(2)=5

y^{^{'}} = \frac{( x ^{2} - y ^{2} )}{x y}, y (2) = 5

y = \frac{x ^{4} + 184}{2 x}

Solution steps

y^{'} (x) = \frac{( x ^{2} - y ^{2} )}{x y}

Solve Bernoulli ODE:

y = \frac{x ^{4} + 184}{2 x}

y = \frac{x ^{4} + 184}{2 x}

\frac{d}{d x} ((\frac{3 x sin ( x )}{3 x + 1})^{3})

\frac{d}{d x} (y + x y)

f (x) = 4 sec (x), at (\frac{π}{6})

f (x) = \frac{x - 1}{x + 1}

\frac{d y}{d x} = \frac{( x - 4 )}{y + 6}

What is the solution for y^'=((x^2-y^2))/(xy),y(2)=5 ?
The solution for y^'=((x^2-y^2))/(xy),y(2)=5 is y=(sqrt(x^4+184))/(sqrt(2)x)