What is the integral of cos(x)sin^4(x) ?

The integral of cos(x)sin^4(x) is (sin^5(x))/5+C

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integral of cos(x)sin^4(x)

\int cos (x) sin^{4} (x) d x

\frac{sin ^{5} ( x )}{5} + C

Solution steps

\int cos (x) sin^{4} (x) d x

Apply u-substitution

: \int u^{4} d u

= \int u^{4} d u

Apply the Power Rule

: \frac{u ^{5}}{5}

= \frac{u ^{5}}{5}

Substitute back

u = sin (x)

= \frac{sin ^{5} ( x )}{5}

Add a constant to the solution

= \frac{sin ^{5} ( x )}{5} + C

f (x) = \frac{7}{2} x^{2} - 5 x + 1

θ \to 0 lim (θ cot (5 θ))

\frac{d}{d x} (\frac{x ^{2} - 9}{x ^{2} + 9})

x^{^{''}} + x^{^{'}} + 2 x = 0

\frac{d y}{d x} = 2 y (3 - y)

What is the integral of cos(x)sin^4(x) ?
The integral of cos(x)sin^4(x) is (sin^5(x))/5+C