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受欢迎的微积分 >

tangent y=sin(7x)+cos(2x)

解答

切线

y = sin (7 x) + cos (2 x)

解答

y = (cos (7 a_{0}) \cdot 7 - sin (2 a_{0}) \cdot 2) x + sin (7 a_{0}) + cos (2 a_{0}) - (cos (7 a_{0}) \cdot 7 - sin (2 a_{0}) \cdot 2) a_{0}

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, sin (7 a_{0}) + cos (2 a_{0}))

计算

y = sin (7 x) + cos (2 x)

的斜率:

\frac{d y}{d x} = cos (7 x) \cdot 7 - sin (2 x) \cdot 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = cos (7 a_{0}) \cdot 7 - sin (2 a_{0}) \cdot 2

找到斜率 m=

cos (7 a_{0}) 7 - sin (2 a_{0}) 2

且穿过

(a_{0}, sin (7 a_{0}) + cos (2 a_{0}))

的直线:

y = (cos (7 a_{0}) \cdot 7 - sin (2 a_{0}) \cdot 2) x + sin (7 a_{0}) + cos (2 a_{0}) - (cos (7 a_{0}) \cdot 7 - sin (2 a_{0}) \cdot 2) a_{0}

y = (cos (7 a_{0}) \cdot 7 - sin (2 a_{0}) \cdot 2) x + sin (7 a_{0}) + cos (2 a_{0}) - (cos (7 a_{0}) \cdot 7 - sin (2 a_{0}) \cdot 2) a_{0}

作图

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