derivative f(t)=2t^2+3t-6

Lösung

ableitung von

f (t) = 2 t^{2} + 3 t - 6

4 t + 3

Schritte zur Lösung

\frac{d}{d t} (2 t^{2} + 3 t - 6)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (2 t^{2}) + \frac{d}{d t} (3 t) - \frac{d}{d t} (6)

\frac{d}{d t} (2 t^{2}) = 4 t

\frac{d}{d t} (3 t) = 3

\frac{d}{d t} (6) = 0

= 4 t + 3 - 0

Vereinfache

= 4 t + 3

\frac{\partial}{\partial x} (\frac{( a x + b y )}{c x + d y})

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