xy^{''}+y^'=1

Lösung

x y^{^{''}} + y^{^{'}} = 1

y = c_{1} + c_{2} ln (x) + x

Schritte zur Lösung

x y^{''} (x) + y^{'} (x) = 1

Solve linear ODE:

y = c_{1} + c_{2} ln (x) + x

y = c_{1} + c_{2} ln (x) + x

\frac{\partial}{\partial x} (6 x sin (x + 2 y - z))

\frac{\partial}{\partial y} (2 x^{2} + 2 y - 8)

\int (csc^{2} (x) + 4) d x

\frac{d}{d x} (x^{2} \cdot e^{2 x})

\int \frac{2 ^{2 x}}{1 + 2 ^{2 x}} d x