(\partial)/(\partial x)(x^2y^3+xy-2)

Lösung

\frac{\partial}{\partial x} (x^{2} y^{3} + x y - 2)

2 x y^{3} + y

Schritte zur Lösung

\frac{\partial}{\partial x} (x^{2} y^{3} + x y - 2)

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2} y^{3}) + \frac{\partial}{\partial x} (x y) - \frac{\partial}{\partial x} (2)

\frac{\partial}{\partial x} (x^{2} y^{3}) = 2 y^{3} x

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (2) = 0

= 2 y^{3} x + y - 0

Vereinfache

= 2 x y^{3} + y

\int_{l n (4)}^{l n (9)} e^{\frac{x}{2}} d x

d er i v a t i v e f (x) = sin (\frac{1}{x ^{2}})

\int \frac{cos ^{6} ( x )}{sin ^{10} ( x )} d x

y^{^{''}} + \frac{a _{1^{2}} π ^{2}}{a _{2}^{2}} a_{3}^{2} y = 0

in v erse l a pl a ce sin (s)