(d^4)/(dx^4)(18e^{x^2})

Lösung

\frac{d ^{4}}{d x ^{4}} (18 e^{x^{2}})

36 (8 e^{x^{2}} x^{4} + 24 e^{x^{2}} x^{2} + 6 e^{x^{2}})

Schritte zur Lösung

\frac{d ^{4}}{d x ^{4}} (18 e^{x^{2}})

\frac{d}{d x} (18 e^{x^{2}}) = 36 e^{x^{2}} x

= \frac{d ^{3}}{d x ^{3}} (36 e^{x^{2}} x)

\frac{d}{d x} (36 e^{x^{2}} x) = 36 (2 e^{x^{2}} x^{2} + e^{x^{2}})

= \frac{d ^{2}}{d x ^{2}} (36 (2 e^{x^{2}} x^{2} + e^{x^{2}}))

\frac{d}{d x} (36 (2 e^{x^{2}} x^{2} + e^{x^{2}})) = 36 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x)

= \frac{d}{d x} (36 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x))

\frac{d}{d x} (36 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x)) = 36 (8 e^{x^{2}} x^{4} + 24 e^{x^{2}} x^{2} + 6 e^{x^{2}})

= 36 (8 e^{x^{2}} x^{4} + 24 e^{x^{2}} x^{2} + 6 e^{x^{2}})

x \to \infty lim (2^{x} - 1)

\frac{d}{d x} (4 e^{- x^{4}})

\int w^{2} ln (w^{6} - 1) d w

\int \frac{1 - y ^{2}}{3 y} d y

y^{^{''}} + y = x^{2} + 1