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Beliebt Rechnen >

y^'(x-1)+y(x-2)=0

Lösung

y^{^{'}} \cdot (x - 1) + y \cdot (x - 2) = 0

Lösung

y = e^{- x + c_{1}} x - e^{- x + c_{1}}

Schritte zur Lösung

y^{'} (x) \cdot (x - 1) + y \cdot (x - 2) = 0

Solve separable ODE:

y = e^{- x + c_{1}} x - e^{- x + c_{1}}

y = e^{- x + c_{1}} x - e^{- x + c_{1}}

Graph

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