What is the solution for (dy)/(dt)+4y=2e^{-3t} ?

The solution for (dy)/(dt)+4y=2e^{-3t} is y= 2/(e^{3t)}+(c_{1})/(e^{4t)}

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(dy)/(dt)+4y=2e^{-3t}

\frac{d y}{d t} + 4 y = 2 e^{- 3 t}

y = \frac{2}{e ^{3 t}} + \frac{c _{1}}{e ^{4 t}}

Solution steps

\frac{d y}{d t} + 4 y = 2 e^{- 3 t}

Solve linear ODE:

y = \frac{2}{e ^{3 t}} + \frac{c _{1}}{e ^{4 t}}

y = \frac{2}{e ^{3 t}} + \frac{c _{1}}{e ^{4 t}}

\frac{d}{d x} (x^{52} - \frac{1}{x ^{2}})

l o n g d i v i s i o n \frac{x ^{2} - 1}{2 x - 3}

\int 5 e^{4 x + e^{4 x}} d x

d er i v a t i v e f (x) = (x^{3} + 3 x + 6) (4 + \frac{1}{x ^{2}})

\int cos (\frac{x}{4}) sin (\frac{x}{4}) d x

What is the solution for (dy)/(dt)+4y=2e^{-3t} ?
The solution for (dy)/(dt)+4y=2e^{-3t} is y= 2/(e^{3t)}+(c_{1})/(e^{4t)}