(\partial)/(\partial x)(sin(6xy+7yz+9xz))

Lösung

\frac{\partial}{\partial x} (sin (6 x y + 7 yz + 9 x z))

cos (6 x y + 7 yz + 9 x z) (6 y + 9 z)

Schritte zur Lösung

\frac{\partial}{\partial x} (sin (6 x y + 7 yz + 9 x z))

Behandle

y, z

als Konstanten

Wende die Kettenregel an:

cos (6 x y + 7 yz + 9 x z) \frac{\partial}{\partial x} (6 x y + 7 yz + 9 x z)

= cos (6 x y + 7 yz + 9 x z) \frac{\partial}{\partial x} (6 x y + 7 yz + 9 x z)

\frac{\partial}{\partial x} (6 x y + 7 yz + 9 x z) = 6 y + 9 z

= cos (6 x y + 7 yz + 9 x z) (6 y + 9 z)

\int (4 x - \frac{2}{x} + 5 sin (x)) d x

x \to \infty lim ((4)^{x})

f^{^{'}} (x) = sec (2 x) tan (2 x) - \frac{4}{x ^{2}}

n = 0 \sum \infty x^{n} \frac{1}{n}

\frac{d}{d x} (2 x^{3} + \frac{45 x ^{2}}{2} + 21 x + 4)