derivative of 10sqrt(0.6x+7)

Lösung

\frac{d}{d x} (10 0.6 x + 7)

\frac{3}{0.6 x + 7}

Schritte zur Lösung

\frac{d}{d x} (10 0.6 x + 7)

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 \frac{d}{d x} (0.6 x + 7)

Wende die Kettenregel an:

\frac{1}{2 0.6 x + 7} \frac{d}{d x} (0.6 x + 7)

= \frac{1}{2 0.6 x + 7} \frac{d}{d x} (0.6 x + 7)

\frac{d}{d x} (0.6 x + 7) = 0.6

= 10 \cdot \frac{1}{2 0.6 x + 7} \cdot 0.6

Vereinfache

10 \cdot \frac{1}{2 0.6 x + 7} \cdot 0.6 : \frac{3}{0.6 x + 7}

= \frac{3}{0.6 x + 7}

t an g e n t f (x) = x^{2} + 40, at x = 3

\frac{d y}{d x} + 7 (tan (7 x)) y = 2 cos (7 x)

x \to - 4 lim (8 - x)

\int \frac{6 ^{x}}{x} d x

\frac{\partial}{\partial z} (tan (2 + 2 x^{2} y^{4} z^{2}))