extreme f(x)=-x^2+7

Lösung

extrempunkte

f (x) = - x^{2} + 7

Maximum (0, 7)

Schritte zur Lösung

f^{'} (x) = - 2 x

Intervalle finden:

Ansteigend

: - \infty < x < 0,

Absteigend

: 0 < x < \infty

Stecke

x = 0

- x^{2} + 7 : 7

Maximum (0, 7)

e x t re m e f (x) = 2 x^{3} + 3 x^{2} - 36 x + 15

e x t re m e y = e^{(2 - x)} + x^{2} - \frac{x}{2}

e x t re m e f (x) = - 6 x^{2} - 9 x y - 7 y^{2} - 99 x - 96 y + 5

e x t re m e P (x, y) = x + y^{2} - 10 x^{2} y^{2} + 9 y^{6}

e x t re m e f (x) = - x^{\frac{2}{3}} (x - 1), - 1 \leq x \leq 1