extreme f(x)=4x^2-32ln(x)

Lösung

extrempunkte

f (x) = 4 x^{2} - 32 ln (x)

Minimum (2, 16 - 32 ln (2))

Schritte zur Lösung

f^{'} (x) = 8 x - \frac{32}{x}

Intervalle finden:

Absteigend

: 0 < x < 2,

Ansteigend

: 2 < x < \infty

Stecke

x = 2

4 x^{2} - 32 ln (x) : 16 - 32 ln (2)

Minimum (2, 16 - 32 ln (2))

e x t re m e y = - 6 - z^{2} - x^{2}

e x t re m e f (x, y) = - x^{2} - 2 y^{2} + x y + x + 3 y

e x t re m e f (x) = - \frac{2}{3} x^{3} + 2 x^{2} + 6 x - 50

e x t re m e f (x) = x^{5} - 20 x^{4} + 8, 0 \leq x \leq 17

e x t re m e P (q, r) = 4 - q + r