What is the extreme f(x,y)=-3x^2+2xy-y^2+14x+2y+10 ?

The extreme f(x,y)=-3x^2+2xy-y^2+14x+2y+10 is Maximum(4,5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=-3x^2+2xy-y^2+14x+2y+10

extreme points

f (x, y) = - 3 x^{2} + 2 x y - y^{2} + 14 x + 2 y + 10

Maximum (4, 5)

Solution steps

Find the critical points:

(4, 5)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = 8

Check the sign of at each critical point

Check critical point

(4, 5) :

Maximum

Maximum (4, 5)

f (x) = x^{2} lo g_{6} (x)

y = \frac{ln ( x )}{x ^{4}}

250 + 8 x^{3} + x^{4}

f (x) = e^{3 x^{2} + 8 y^{2} + 13}

\frac{3 x}{x ^{2} + 1}

What is the extreme f(x,y)=-3x^2+2xy-y^2+14x+2y+10 ?
The extreme f(x,y)=-3x^2+2xy-y^2+14x+2y+10 is Maximum(4,5)