extreme f(x)=17+7x+x^2

Lösung

extrempunkte

f (x) = 17 + 7 x + x^{2}

Minimum (- \frac{7}{2}, \frac{19}{4})

Schritte zur Lösung

f^{'} (x) = 2 x + 7

Intervalle finden:

Absteigend

: - \infty < x < - \frac{7}{2},

Ansteigend

: - \frac{7}{2} < x < \infty

Stecke

x = - \frac{7}{2}

17 + 7 x + x^{2} : \frac{19}{4}

Minimum (- \frac{7}{2}, \frac{19}{4})

e x t re m e 5 x^{4} + x^{3} - 9 x^{2} + 2 x + 5

e x t re m e f (x, y) = x^{2} - x y - y^{2} - 3 x - y

e x t re m e f (x, y) = x^{2} (2 + y^{2}) + y ln (y)

e x t re m e f (x) = 2 x^{3} - 3 x^{2} - 12

e x t re m e f (x) = x^{3} + 12 x^{2} - 27 x + 8 [- 10]