extreme f(x)=380x^2-3800x^3

Lösung

extrempunkte

f (x) = 380 x^{2} - 3800 x^{3}

Minimum (0, 0), Maximum (\frac{1}{15}, \frac{76}{135})

Schritte zur Lösung

f^{'} (x) = 760 x - 11400 x^{2}

Intervalle finden:

Absteigend

: - \infty < x < 0,

Ansteigend

: 0 < x < \frac{1}{15},

Absteigend

: \frac{1}{15} < x < \infty

Stecke

x = 0

380 x^{2} - 3800 x^{3} : 0

Minimum (0, 0)

Stecke

x = \frac{1}{15}

380 x^{2} - 3800 x^{3} : \frac{76}{135}

Maximum (\frac{1}{15}, \frac{76}{135})

Minimum (0, 0), Maximum (\frac{1}{15}, \frac{76}{135})

e x t re m e f (x) = 3 x^{4} - 4 x^{3} - 12 x^{2} + 1 [- 2.3]

e x t re m e f (x) = 8 x^{3} - 3 x y + y^{3}

e x t re m e - x^{2} + 5 x - 2

e x t re m e f (x) = 6 x^{2} + 500 x + 8000

e x t re m e f (x, y) = x ln (y) + y e^{x} - x^{2}