extreme x^2+3x-4

解答

极值点

x^{2} + 3 x - 4

极小值 (- \frac{3}{2}, - \frac{25}{4})

求解步骤

f^{'} (x) = 2 x + 3

Find intervals:

递减

: - \infty < x < - \frac{3}{2},

递增

: - \frac{3}{2} < x < \infty

将

x = - \frac{3}{2}

代入

x^{2} + 3 x - 4 : - \frac{25}{4}

极小值 (- \frac{3}{2}, - \frac{25}{4})

e x t re m e f (x) = 6 x^{4} - 8 x^{3} + 2

e x t re m e f (x) = \frac{( 4 x - 18 )}{( x - 9 ) ^{2}}

e x t re m e f (x, y) = 11 x^{2} - 2 x^{3} + 2 y^{2} + 4 x y

e x t re m e y (x, t) = x (- 2 t + 2)

e x t re m e y = 2 x^{3} - 6 x