extreme f(x)=6x^3-x^2-5x+7

Lösung

extrempunkte

f (x) = 6 x^{3} - x^{2} - 5 x + 7

Maximum (\frac{1 - 91}{18}, \frac{91 91 - 136}{486} + 7), Minimum (\frac{1 + 91}{18}, \frac{- 136 - 91 91}{486} + 7)

Schritte zur Lösung

f^{'} (x) = 18 x^{2} - 2 x - 5

Intervalle finden:

Ansteigend

: - \infty < x < \frac{- 91 + 1}{18},

Absteigend

: \frac{- 91 + 1}{18} < x < \frac{91 + 1}{18},

Ansteigend

: \frac{91 + 1}{18} < x < \infty

Stecke

x = \frac{1 - 91}{18}

6 x^{3} - x^{2} - 5 x + 7 : \frac{91 91 - 136}{486} + 7

Maximum (\frac{1 - 91}{18}, \frac{91 91 - 136}{486} + 7)

Stecke

x = \frac{1 + 91}{18}

6 x^{3} - x^{2} - 5 x + 7 : \frac{- 136 - 91 91}{486} + 7

Minimum (\frac{1 + 91}{18}, \frac{- 136 - 91 91}{486} + 7)

Maximum (\frac{1 - 91}{18}, \frac{91 91 - 136}{486} + 7), Minimum (\frac{1 + 91}{18}, \frac{- 136 - 91 91}{486} + 7)

e x t re m e f (x) = γ (x + 1)

e x t re m e f (x) = \frac{x}{x ^{2} - 64}

e x t re m e f (x) = \frac{x}{x ^{2} - x + 2}, - 2 \leq x \leq 1

e x t re m e - 4.9 t^{2} + 283 t + 353

e x t re m e y = 0 (x + 0) (x + (- 8))