extreme f(x)=x^2-2x+5[-1.4]

Lösung

extrempunkte

f (x) = x^{2} - 2 x + 5 [- 1.4]

Minimum (1, - 8)

Schritte zur Lösung

f^{'} (x) = 2 x - 2

Intervalle finden:

Absteigend

: - \infty < x < 1,

Ansteigend

: 1 < x < \infty

Stecke

x = 1

x^{2} - 2 x + 5 [- 1.4] : - 8

Minimum (1, - 8)

e x t re m e 2 x^{4} - 196 x^{2} - 3

e x t re m e f (x) = - x^{2} - y^{2} + 8 x + 8 y

e x t re m e f (x, y) = x^{3} + 8 x^{2} y^{2} - 8 y^{3} - x + y

e x t re m e f (t) = 4 t^{3} - 36 t^{2} + 10, t \geq 0

e x t re m e f (x) = 3 x^{4} + 20 x^{3} - 36 x^{2} - 4