extreme x^3+12x^2-27x+2

Lösung

extrempunkte

x^{3} + 12 x^{2} - 27 x + 2

Maximum (- 9, 488), Minimum (1, - 12)

Schritte zur Lösung

f^{'} (x) = 3 x^{2} + 24 x - 27

Intervalle finden:

Ansteigend

: - \infty < x < - 9,

Absteigend

: - 9 < x < 1,

Ansteigend

: 1 < x < \infty

Stecke

x = - 9

x^{3} + 12 x^{2} - 27 x + 2 : 488

Maximum (- 9, 488)

Stecke

x = 1

x^{3} + 12 x^{2} - 27 x + 2 : - 12

Minimum (1, - 12)

Maximum (- 9, 488), Minimum (1, - 12)

e x t re m e f (x) = x^{3} - 9 x^{2} + 15 x - 4

e x t re m e P (x, y) = 3 x^{2} y + 4 x y^{2} - y^{- 4}

e x t re m e f (x) = (x + 10) (\frac{60}{x} + 6)

e x t re m e f (x) = \frac{1}{2} x^{4} - 4 x^{2} + 5

e x t re m e f (x) = \frac{1}{2} x^{4} - 4 x^{2} + 3