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Beliebt Funktionen >

extreme 20-0.06x+0.0002x^2

Lösung

extrempunkte

20 - 0.06 x + 0.0002 x^{2}

Lösung

Minimum (\frac{0.06}{0.0004}, 15.5)

Schritte zur Lösung

f^{'} (x) = 0.0004 x - 0.06

Intervalle finden:

Absteigend

: - \infty < x < \frac{0.06}{0.0004},

Ansteigend

: \frac{0.06}{0.0004} < x < \infty

Stecke

x = \frac{0.06}{0.0004}

in

20 - 0.06 x + 0.0002 x^{2} : 15.5

Minimum (\frac{0.06}{0.0004}, 15.5)

Graph

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