extreme f(x)=((x^2-11x+82))/(x-9)

Lösung

extrempunkte

f (x) = \frac{( x ^{2} - 11 x + 82 )}{x - 9}

Maximum (1, - 9), Minimum (17, 23)

Schritte zur Lösung

f^{'} (x) = \frac{x ^{2} - 18 x + 17}{( x - 9 ) ^{2}}

Intervalle finden:

Ansteigend

: - \infty < x < 1,

Absteigend

: 1 < x < 9,

Absteigend

: 9 < x < 17,

Ansteigend

: 17 < x < \infty

Stecke

x = 1

\frac{x ^{2} - 11 x + 82}{x - 9} : - 9

Maximum (1, - 9)

Stecke

x = 17

\frac{x ^{2} - 11 x + 82}{x - 9} : 23

Minimum (17, 23)

Maximum (1, - 9), Minimum (17, 23)

e x t re m e p (x) = x^{2} (a + 3) x^{3} + 2 x + a^{2} + 5

e x t re m e R (x, y) = x^{2} + 5 x y + 6 y^{2} + 7 x + 17 y + 12

e x t re m e f (x) = - 10 x^{2} + 1660 x - 49000

e x t re m e f (x) = e^{x^{2} + 3 y^{2} - 2 x}

e x t re m e f (x) = 4 - (8 + 7 x)^{\frac{2}{7}}