extreme p(x)=9x^4+9x^2-18

Lösung

extrempunkte

p (x) = 9 x^{4} + 9 x^{2} - 18

Minimum (0, - 18)

Schritte zur Lösung

f^{'} (x) = 36 x^{3} + 18 x

Intervalle finden:

Absteigend

: - \infty < x < 0,

Ansteigend

: 0 < x < \infty

Stecke

x = 0

9 x^{4} + 9 x^{2} - 18 : - 18

Minimum (0, - 18)

e x t re m e f (x) = 2 x^{3} + 6 x^{2} - 48 x + 6 [4.6]

e x t re m e f (x) = 3 sin (x), - π \leq x \leq 2 π

e x t re m e f (x, y) = x^{2} + 10 x y + y^{2}

e x t re m e f (x) = x^{3} - \frac{9}{2} x^{2} - 54 x + 12

e x t re m e y = x^{2} - 3 x - 70