extreme f(x)=x^2-6x+12

Lösung

extrempunkte

f (x) = x^{2} - 6 x + 12

Minimum (3, 3)

Schritte zur Lösung

f^{'} (x) = 2 x - 6

Intervalle finden:

Absteigend

: - \infty < x < 3,

Ansteigend

: 3 < x < \infty

Stecke

x = 3

x^{2} - 6 x + 12 : 3

Minimum (3, 3)

e x t re m e f (t) = \frac{x}{x + 25} [0.9]

e x t re m e f (x) = - x^{3} + 3 x^{2} + 429 x + 5242

e x t re m e f (t) = 108 t - t^{3}

e x t re m e f (x) = 2 x^{3} + 6 x^{2} - 90 x + 1, - 5 \leq x \leq 7

e x t re m e f (x) = x^{4} + 2 x^{3} - 2 x^{2} + 2 x + 1