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受欢迎的函数 >

extreme f(x)= x/(x-9),11<= x<= 13

解答

极值点

f (x) = \frac{x}{x - 9}, 11 \leq x \leq 13

解答

极大值 (11, \frac{11}{2}), 极小值 (13, \frac{13}{4})

求解步骤

找到临界点:

x = 11, x = 13

\frac{x}{x - 9}, 11 \leq x \leq 13

的定义域

: 11 \leq x \leq 13

Find intervals:

递减

: 11 < x < 13

将极值点

x = 11

代入

\frac{x}{x - 9} \Rightarrow y = \frac{11}{2}

极大值 (11, \frac{11}{2})

将极值点

x = 13

代入

\frac{x}{x - 9} \Rightarrow y = \frac{13}{4}

极小值 (13, \frac{13}{4})

极大值 (11, \frac{11}{2}), 极小值 (13, \frac{13}{4})

作图

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