What is the extreme f(x)=-8x^3+6x+6 ?

The extreme f(x)=-8x^3+6x+6 is Minimum(-1/2 ,4),Maximum(1/2 ,8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-8x^3+6x+6

extreme points

f (x) = - 8 x^{3} + 6 x + 6

Minimum (- \frac{1}{2}, 4), Maximum (\frac{1}{2}, 8)

Solution steps

f^{'} (x) = - 24 x^{2} + 6

Find intervals:

Decreasing

: - \infty < x < - \frac{1}{2},

Increasing

: - \frac{1}{2} < x < \frac{1}{2},

Decreasing

: \frac{1}{2} < x < \infty

Plug

x = - \frac{1}{2}

into

- 8 x^{3} + 6 x + 6 : 4

Minimum (- \frac{1}{2}, 4)

Plug

x = \frac{1}{2}

into

- 8 x^{3} + 6 x + 6 : 8

Maximum (\frac{1}{2}, 8)

Minimum (- \frac{1}{2}, 4), Maximum (\frac{1}{2}, 8)

f (x) = \frac{x + 1}{x ^{2} - 2 x - 3}

f (x) = x^{3} - 1

f (x) = 5 x - 2

\frac{x + 2}{x - 1}

y = \frac{x + 8}{x ^{2} - 9}

What is the extreme f(x)=-8x^3+6x+6 ?
The extreme f(x)=-8x^3+6x+6 is Minimum(-1/2 ,4),Maximum(1/2 ,8)